(y^3+3y^2-5)+(3y^3+4y-4)=

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Solution for (y^3+3y^2-5)+(3y^3+4y-4)= equation: 


Simplifying
(y3 + 3y2 + -5) + (3y3 + 4y + -4) = 0

Reorder the terms:
(-5 + 3y2 + y3) + (3y3 + 4y + -4) = 0

Remove parenthesis around (-5 + 3y2 + y3)
-5 + 3y2 + y3 + (3y3 + 4y + -4) = 0

Reorder the terms:
-5 + 3y2 + y3 + (-4 + 4y + 3y3) = 0

Remove parenthesis around (-4 + 4y + 3y3)
-5 + 3y2 + y3 + -4 + 4y + 3y3 = 0

Reorder the terms:
-5 + -4 + 4y + 3y2 + y3 + 3y3 = 0

Combine like terms: -5 + -4 = -9
-9 + 4y + 3y2 + y3 + 3y3 = 0

Combine like terms: y3 + 3y3 = 4y3
-9 + 4y + 3y2 + 4y3 = 0

Solving
-9 + 4y + 3y2 + 4y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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